gvsu/cs677/hw6/hw.tex
josh fb79f823d0 updated hw.tex for hw6
git-svn-id: svn://anubis/gvsu@231 45c1a28c-8058-47b2-ae61-ca45b979098e
2008-11-15 17:29:45 +00:00

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% Preamble
\documentclass[11pt,fleqn]{article}
\usepackage{amsmath, amsthm, amssymb}
\usepackage{fancyhdr}
\oddsidemargin -0.25in
\textwidth 6.75in
\topmargin -0.5in
\headheight 0.75in
\headsep 0.25in
\textheight 8.75in
\pagestyle{fancy}
\renewcommand{\headrulewidth}{0pt}
\renewcommand{\footrulewidth}{0pt}
\fancyhf{}
\lhead{HW Chap. 6\\\ \\\ }
\rhead{Josh Holtrop\\2008-11-19\\CS 677}
\rfoot{\thepage}
\begin{document}
\noindent
\begin{enumerate}
\item[1.]{
The obvious benefit of using non-blocking communication is that
the calling process does not block while the communication is taking
place.
This leaves the process free to do further computation or work on
something else.
Another benefit of non-blocking communication is that certain types
of deadlocks can be avoided by not having the Send function block
until the message is received (for example, when two machines are
both doing a send operation followed by a receive operation).
One challenge to using non-blocking communication is that it is
harder to program safely.
The programmer must take more care to ensure that data being used
in non-blocking communication is not modified while it is being used.
A second challenge with using non-blocking communication is that if
synchronization is necessary (i.e. the sender wants to know when
the message was received), then they must manually poll to obtain
this information.
}
\vskip 1em
\item[2.]{
Assume the mesh size is $n \times n$.
Further assume that the node doing the scatter is located in the
top left corner of the mesh.
First, the total data is divided $n$ ways.
1 of these sections are sent to the node doing the scattering,
and $n-1$ of these are sent to the next node down.
The nodes along the left continue sending data sections down, each
taking one section for itself.
Then, all of the left edges break each of these $n$ sections into
$n$ parts, and repeat the previous process to distribute these
$n$ subparts to the nodes to their right.
This method will take $2n$ steps to complete.
The message transfer size is not fixed.
The messages at the beginning (closer to the scattering node)
are larger and subsequent messages get smaller and smaller as
they get further from the scattering node.
}
\end{enumerate}
\end{document}