define startup stack in linker script, not assembly
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@ -97,6 +97,7 @@ EOF
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env["LIBS"] += %w[gcc]
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env["LIBS"] += %w[gcc]
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env["OBJDUMP"] = "i686-elf-objdump"
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env["OBJDUMP"] = "i686-elf-objdump"
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env.Program("^/hos.elf", glob("src/**/*.{S,c}"))
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env.Program("^/hos.elf", glob("src/**/*.{S,c}"))
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env.depends("#{env.build_root}/hos.elf", "src/link.ld")
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env.Disassemble("^/hos.elf.txt", "^/hos.elf")
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env.Disassemble("^/hos.elf.txt", "^/hos.elf")
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env.EfiImage("build/hos-efi.img", %w[^/hos.elf])
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env.EfiImage("build/hos-efi.img", %w[^/hos.elf])
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env.BiosImage("build/hos-bios.img", %w[^/hos.elf])
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env.BiosImage("build/hos-bios.img", %w[^/hos.elf])
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38
src/boot.S
38
src/boot.S
@ -1,21 +1,3 @@
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/*
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The multiboot standard does not define the value of the stack pointer register
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(esp) and it is up to the kernel to provide a stack. This allocates room for a
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small stack by creating a symbol at the bottom of it, then allocating 16384
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bytes for it, and finally creating a symbol at the top. The stack grows
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downwards on x86. The stack is in its own section so it can be marked nobits,
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which means the kernel file is smaller because it does not contain an
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uninitialized stack. The stack on x86 must be 16-byte aligned according to the
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System V ABI standard and de-facto extensions. The compiler will assume the
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stack is properly aligned and failure to align the stack will result in
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undefined behavior.
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*/
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.section .bss
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.align 16
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stack_bottom:
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.skip 16384 # 16 KiB
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stack_top:
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/*
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/*
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The linker script specifies _start as the entry point to the kernel and the
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The linker script specifies _start as the entry point to the kernel and the
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bootloader will jump to this position once the kernel has been loaded. It
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bootloader will jump to this position once the kernel has been loaded. It
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@ -25,25 +7,7 @@ doesn't make sense to return from this function as the bootloader is gone.
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.global _start
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.global _start
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.type _start, @function
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.type _start, @function
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_start:
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_start:
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/*
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mov $_stack_end, %esp
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The bootloader has loaded us into 32-bit protected mode on a x86
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machine. Interrupts are disabled. Paging is disabled. The processor
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state is as defined in the multiboot standard. The kernel has full
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control of the CPU. The kernel can only make use of hardware features
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and any code it provides as part of itself. There's no printf
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function, unless the kernel provides its own <stdio.h> header and a
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printf implementation. There are no security restrictions, no
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safeguards, no debugging mechanisms, only what the kernel provides
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itself. It has absolute and complete power over the
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machine.
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*/
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/*
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To set up a stack, we set the esp register to point to the top of the
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stack (as it grows downwards on x86 systems). This is necessarily done
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in assembly as languages such as C cannot function without a stack.
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*/
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mov $stack_top, %esp
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/*
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/*
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This is a good place to initialize crucial processor state before the
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This is a good place to initialize crucial processor state before the
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@ -20,6 +20,14 @@ SECTIONS
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*(.data)
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*(.data)
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}
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}
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_stack_size = 16K;
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.stack (NOLOAD) : ALIGN(4K)
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{
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_stack_start = .;
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. = . + _stack_size;
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_stack_end = .;
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}
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.bss BLOCK(4K) : ALIGN(4K)
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.bss BLOCK(4K) : ALIGN(4K)
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{
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{
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*(COMMON)
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*(COMMON)
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