Test reentering parser for nested inner parses

This commit is contained in:
Josh Holtrop 2026-07-14 11:41:52 -04:00
parent 0aaa44faf4
commit 7ce1f8fc7f
9 changed files with 427 additions and 0 deletions

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<<
#include <stdlib.h>
#include <string.h>
size_t mylexfn(p_context_t * context, p_token_info_t * out_token_info);
>>
ptype int;
lex_fn mylexfn;
drop /\s+/;
token lparen /\(/;
token rparen /\)/;
token plus /\+/;
token num /\d+/ << char b[32]; memcpy(b, match, match_length); b[match_length] = '\0'; $$ = atoi(b); >>
Start -> Expr << $$ = $1; >>
Expr -> num << $$ = $1; >>
Expr -> Expr plus num << $$ = $1 + $3; >>

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<<
import test_parse_inner_nested;
>>
ptype int;
lex_fn mylexfn;
drop /\s+/;
token lparen /\(/;
token rparen /\)/;
token plus /\+/;
token num /\d+/ << int n = 0; foreach (ch; match) { n *= 10; n += (ch - '0'); } $$ = n; >>
Start -> Expr << $$ = $1; >>
Expr -> num << $$ = $1; >>
Expr -> Expr plus num << $$ = $1 + $3; >>

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<<
size_t mylexfn(p_context_t * context, p_token_info_t * out_token_info);
>>
tree;
lex_fn mylexfn;
drop /\s+/;
token lparen /\(/;
token rparen /\)/;
token plus /\+/;
token num /\d+/;
Start -> Expr;
Expr -> num;
Expr -> Expr plus num;

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<<
import test_parse_inner_nested_tree;
>>
tree;
lex_fn mylexfn;
drop /\s+/;
token lparen /\(/;
token rparen /\)/;
token plus /\+/;
token num /\d+/;
Start -> Expr;
Expr -> num;
Expr -> Expr plus num;

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expect(results.status).to eq 0
end
it "supports a reentrant nested parse driven from a custom lex function" do
ext = language == "cpp" ? "c" : language
write_grammar(File.read("spec/parse_inner_nested.#{ext}.propane"))
run_propane(language: language)
compile("spec/test_parse_inner_nested.#{language}", language: language)
results = run_test(language: language)
expect(results.stderr).to eq ""
expect(results.status).to eq 0
end
it "tracks positions across a lex-function nested parse in tree mode" do
ext = language == "cpp" ? "c" : language
write_grammar(File.read("spec/parse_inner_nested_tree.#{ext}.propane"))
run_propane(language: language)
compile("spec/test_parse_inner_nested_tree.#{language}", language: language)
results = run_test(language: language)
expect(results.stderr).to eq ""
expect(results.status).to eq 0
end
it "allows multiple starting rules in tree mode" do
write_grammar <<EOF
tree;

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#include "testparser.h"
#include <assert.h>
#include <string.h>
#include "testutils.h"
/* Grammar (integer evaluator; parentheses handled by the lex function):
* ptype int;
* lex_fn mylexfn;
* token lparen /\(/; token rparen /\)/; token plus /\+/;
* token num /\d+/ << ... atoi ... >>
* Start -> Expr << $$ = $1; >>
* Expr -> num << $$ = $1; >>
* Expr -> Expr plus num << $$ = $1 + $3; >>
*
* The tokens lparen and rparen appear in no grammar rule. Instead, when the
* lex function lexes a '(', it performs a nested parse (p_parse_inner_Start)
* of the parenthesized sub-expression -- reentrantly, while the outer parse is
* still suspended in this callback -- reads the computed value with
* p_result_Start, consumes the ')' that p_parse_inner deliberately left in the
* input, and hands a single synthesized num token carrying that value back to
* the outer parse. Nested groups recurse this process to arbitrary depth. */
size_t mylexfn(p_context_t * context, p_token_info_t * out_token_info)
{
size_t result = p_lex(context, out_token_info);
if (result != P_SUCCESS)
{
return result;
}
if (out_token_info->token == TOKEN_lparen)
{
/* Nested parse of the parenthesized sub-expression, stopping at the
* closing ')' follow token. This re-enters the parser while the outer
* parse is suspended in this lex callback. */
p_token_t follow_tokens[] = { TOKEN_rparen };
size_t inner_result = p_parse_inner_Start(context, follow_tokens, 1u);
if (inner_result != P_SUCCESS)
{
return inner_result;
}
int value = p_result_Start(context);
/* p_parse_inner rewound the input so that ')' was not consumed; consume
* it now. */
p_token_info_t rparen_info;
size_t rparen_result = p_lex(context, &rparen_info);
assert(rparen_result == P_SUCCESS);
assert(rparen_info.token == TOKEN_rparen);
/* Replace the '(' token with a synthesized num carrying the nested
* parse result. */
out_token_info->token = TOKEN_num;
out_token_info->pvalue.v_default = value;
}
return P_SUCCESS;
}
static int eval(char const * input)
{
p_context_t * context = p_context_new((uint8_t const *)input, strlen(input));
assert(p_parse(context) == P_SUCCESS);
int value = p_result(context);
p_context_delete(context);
return value;
}
int main()
{
/* No parentheses: plain outer parse. */
assert_eq(5u, (size_t)eval("2 + 3"));
/* A single group evaluated by the nested parse. */
assert_eq(3u, (size_t)eval("(1 + 2)"));
/* A group in the middle of an outer expression. */
assert_eq(14u, (size_t)eval("2 + (3 + 4) + 5"));
/* Nested groups: the nested parse re-enters itself. */
assert_eq(37u, (size_t)eval("2 + (10 + (20 + 5))"));
assert_eq(15u, (size_t)eval("(1 + 2) + (3 + (4 + 5))"));
return 0;
}

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import testparser;
import testutils;
/* Grammar: see test_parse_inner_nested.c. */
size_t mylexfn(p_context_t * context, p_token_info_t * out_token_info)
{
size_t result = p_lex(context, out_token_info);
if (result != P_SUCCESS)
{
return result;
}
if (out_token_info.token == TOKEN_lparen)
{
/* Nested parse of the parenthesized sub-expression, stopping at the
* closing ')' follow token. This re-enters the parser while the outer
* parse is suspended in this lex callback. */
p_token_t[] follow_tokens = [TOKEN_rparen];
size_t inner_result = p_parse_inner_Start(context, follow_tokens);
if (inner_result != P_SUCCESS)
{
return inner_result;
}
int value = p_result_Start(context);
/* p_parse_inner rewound the input so that ')' was not consumed; consume
* it now. */
p_token_info_t rparen_info;
size_t rparen_result = p_lex(context, &rparen_info);
assert(rparen_result == P_SUCCESS);
assert(rparen_info.token == TOKEN_rparen);
/* Replace the '(' token with a synthesized num carrying the nested
* parse result. */
out_token_info.token = TOKEN_num;
out_token_info.pvalue.v_default = value;
}
return P_SUCCESS;
}
int eval(string input)
{
p_context_t * context = p_context_new(input);
assert(p_parse(context) == P_SUCCESS);
int value = p_result(context);
p_context_delete(context);
return value;
}
int main()
{
return 0;
}
unittest
{
/* No parentheses: plain outer parse. */
assert_eq(5, eval("2 + 3"));
/* A single group evaluated by the nested parse. */
assert_eq(3, eval("(1 + 2)"));
/* A group in the middle of an outer expression. */
assert_eq(14, eval("2 + (3 + 4) + 5"));
/* Nested groups: the nested parse re-enters itself. */
assert_eq(37, eval("2 + (10 + (20 + 5))"));
assert_eq(15, eval("(1 + 2) + (3 + (4 + 5))"));
}

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#include "testparser.h"
#include <assert.h>
#include <string.h>
#include "testutils.h"
/* Grammar (tree generation mode; parentheses handled by the lex function):
* tree;
* lex_fn mylexfn;
* token lparen /\(/; token rparen /\)/; token plus /\+/; token num /\d+/;
* Start -> Expr;
* Expr -> num;
* Expr -> Expr plus num;
*
* The same lexer-driven nested parse as test_parse_inner_nested, but in tree
* generation mode. Each "( ... )" group is parsed by a reentrant
* p_parse_inner_Start() call from the lex function; the resulting subtree is
* discarded and a single synthesized num token is handed to the outer parse.
* The synthesized token's position is set to span the whole group ('(' start
* through ')' end), so this verifies that positions survive the nested-parse
* boundary and land correctly in the outer tree. */
size_t mylexfn(p_context_t * context, p_token_info_t * out_token_info)
{
size_t result = p_lex(context, out_token_info);
if (result != P_SUCCESS)
{
return result;
}
if (out_token_info->token == TOKEN_lparen)
{
p_position_t start_position = out_token_info->position;
/* Reentrant nested parse of the parenthesized sub-expression. */
p_token_t follow_tokens[] = { TOKEN_rparen };
size_t inner_result = p_parse_inner_Start(context, follow_tokens, 1u);
if (inner_result != P_SUCCESS)
{
return inner_result;
}
Start * inner = p_result_Start(context);
assert_not_null(inner);
/* p_parse_inner rewound the input so that ')' was not consumed; consume
* it now. */
p_token_info_t rparen_info;
size_t rparen_result = p_lex(context, &rparen_info);
assert(rparen_result == P_SUCCESS);
assert(rparen_info.token == TOKEN_rparen);
/* The subtree covers the region strictly between the parentheses. */
assert_eq((size_t)(start_position.col + 1u), (size_t)inner->position.col);
assert_eq((size_t)(rparen_info.position.col - 1u), (size_t)inner->end_position.col);
p_tree_delete_Start(inner);
/* Synthesize a num token spanning the entire "( ... )" group. */
out_token_info->token = TOKEN_num;
out_token_info->position = start_position;
out_token_info->end_position = rparen_info.end_position;
}
return P_SUCCESS;
}
int main()
{
/* "(3 + 4) + (5 + 6)": two parenthesized groups, each collapsed by the
* lexer into a single num token spanning its group. */
char const * input = "(3 + 4) + (5 + 6)";
p_context_t * context = p_context_new((uint8_t const *)input, strlen(input));
assert(p_parse(context) == P_SUCCESS);
Start * tree = p_result(context);
assert_not_null(tree);
/* Start -> Expr, where the top Expr is "Expr plus num". */
Expr * top = tree->pExpr;
assert_not_null(top);
assert_not_null(top->pExpr);
assert_not_null(top->pToken2);
assert_not_null(top->pToken3);
/* The '+' joining the two groups is at column 9. */
assert_eq(1u, (size_t)top->pToken2->position.row);
assert_eq(9u, (size_t)top->pToken2->position.col);
/* Right operand: synthesized num for "(5 + 6)", spanning columns 11..17. */
assert_eq(1u, (size_t)top->pToken3->position.row);
assert_eq(11u, (size_t)top->pToken3->position.col);
assert_eq(1u, (size_t)top->pToken3->end_position.row);
assert_eq(17u, (size_t)top->pToken3->end_position.col);
/* Left operand: Expr -> num, the synthesized num for "(3 + 4)", spanning
* columns 1..7. */
Expr * left = top->pExpr;
assert_not_null(left->pToken1);
assert_eq(1u, (size_t)left->pToken1->position.row);
assert_eq(1u, (size_t)left->pToken1->position.col);
assert_eq(1u, (size_t)left->pToken1->end_position.row);
assert_eq(7u, (size_t)left->pToken1->end_position.col);
/* The whole tree spans columns 1..17. */
assert_eq(1u, (size_t)tree->position.col);
assert_eq(17u, (size_t)tree->end_position.col);
p_tree_delete(tree);
p_context_delete(context);
return 0;
}

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import testparser;
import testutils;
/* Grammar: see test_parse_inner_nested_tree.c. */
size_t mylexfn(p_context_t * context, p_token_info_t * out_token_info)
{
size_t result = p_lex(context, out_token_info);
if (result != P_SUCCESS)
{
return result;
}
if (out_token_info.token == TOKEN_lparen)
{
p_position_t start_position = out_token_info.position;
/* Reentrant nested parse of the parenthesized sub-expression. */
p_token_t[] follow_tokens = [TOKEN_rparen];
size_t inner_result = p_parse_inner_Start(context, follow_tokens);
if (inner_result != P_SUCCESS)
{
return inner_result;
}
Start * inner = p_result_Start(context);
assert(inner !is null);
/* p_parse_inner rewound the input so that ')' was not consumed; consume
* it now. */
p_token_info_t rparen_info;
size_t rparen_result = p_lex(context, &rparen_info);
assert(rparen_result == P_SUCCESS);
assert(rparen_info.token == TOKEN_rparen);
/* The subtree covers the region strictly between the parentheses. */
assert_eq(start_position.col + 1u, inner.position.col);
assert_eq(rparen_info.position.col - 1u, inner.end_position.col);
p_tree_delete_Start(inner);
/* Synthesize a num token spanning the entire "( ... )" group. */
out_token_info.token = TOKEN_num;
out_token_info.position = start_position;
out_token_info.end_position = rparen_info.end_position;
}
return P_SUCCESS;
}
int main()
{
return 0;
}
unittest
{
/* "(3 + 4) + (5 + 6)": two parenthesized groups, each collapsed by the
* lexer into a single num token spanning its group. */
string input = "(3 + 4) + (5 + 6)";
p_context_t * context = p_context_new(input);
assert(p_parse(context) == P_SUCCESS);
Start * tree = p_result(context);
assert(tree !is null);
/* Start -> Expr, where the top Expr is "Expr plus num". */
Expr * top = tree.pExpr;
assert(top !is null);
assert(top.pExpr !is null);
assert(top.pToken2 !is null);
assert(top.pToken3 !is null);
/* The '+' joining the two groups is at column 9. */
assert_eq(1u, top.pToken2.position.row);
assert_eq(9u, top.pToken2.position.col);
/* Right operand: synthesized num for "(5 + 6)", spanning columns 11..17. */
assert_eq(1u, top.pToken3.position.row);
assert_eq(11u, top.pToken3.position.col);
assert_eq(1u, top.pToken3.end_position.row);
assert_eq(17u, top.pToken3.end_position.col);
/* Left operand: Expr -> num, the synthesized num for "(3 + 4)", spanning
* columns 1..7. */
Expr * left = top.pExpr;
assert(left.pToken1 !is null);
assert_eq(1u, left.pToken1.position.row);
assert_eq(1u, left.pToken1.position.col);
assert_eq(1u, left.pToken1.end_position.row);
assert_eq(7u, left.pToken1.end_position.col);
/* The whole tree spans columns 1..17. */
assert_eq(1u, tree.position.col);
assert_eq(17u, tree.end_position.col);
p_tree_delete(tree);
p_context_delete(context);
}